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Solve for y: y-3/y+7 - 5/y = 0 (fractions)
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\[\frac{y-3}{y+7}-\frac{5}{y}=0\] like that?
yes!!
SATELLITE TO THE RESCUEE!
wish I could write them like that!
WIRELESS rescue!
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get \[\frac{y-3}{y+7}=\frac{5}{y}\] so \[y(y-3)=5(y+7)\] \[y^2-3y=5y+35\] \[y^2-8y-35=0\]
solve for y, right.
yup
yes, solve for y
that isnt solve for y! ^ :(
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?
y=??
its like y = 11.14 y = -3.14
i get \[y^2-8y=35\] so \[(y-4)^2=35+16=51\] \[y-4=\pm\sqrt{51}\] amd \[y=4\pm\sqrt{51}\]
now let me check the algebra
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^.^
looks good to me!
Awesome! Except, lol, I'm not sure I understand the symbols in the answer... y=4/51 ???
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