Question

x^2-2x-5>orequal to 3

Answer 1

{{x >= 4}, {x <= -2}}

Answer 2

start with
\[x^2-2x-8\geq 0\] then find the zeros. since this is a parabola facing up with will be positive outside them

Answer 3

(x-4)(x+2)>=0

Answer 4

\[x \le -2 \]

\[x \ge +4\]

Answer 5

\[(x-4)(x+2)\geq 0\]wow we all got this one!

Answer 6

inf?

Answer 7

oops i forgot to be brackets

Answer 8

(-inf,-2] U [4,inf)

Answer 9

\[\Huge \infty\]

Answer 10

\[(-\infty,-2)\cup (4,\infty)\]

Answer 11

you mean to include -2 and 4

Answer 12

\[\Huge \frac{\infty}{\color{blue}{\text{saifoooooo!}}}\]

Answer 13

\[(-\infty,-2] \cup [4,\infty)\]

Answer 14

yeah yeah that is the second time i made that mistake tonight

Answer 15

\[(-\infty,-2] \cup [4,\infty)\]

Answer 16

i win :)

Answer 17

as per usual

Answer 18

lol