Question

When adding the fractions, do I have this right?
3/p+3 + 4/p =

7/p+3 ???

Answer 1

not exactly

Answer 2

p^2 + 3??

Answer 3

You have to have the same denominator before you add them

Answer 4

to add these fractions, make common denominator p*(p+3)

Answer 5

10/p?

Answer 6

I meant 7/p?
gosh, lol. shooting in the dark!

Answer 7

\[\frac{3}{p+3}+\frac{4}{p}\]


\[\frac{3p}{p(p+3)}+\frac{4}{p}\]


\[\frac{3p}{p(p+3)}+\frac{4(p+3)}{p(p+3)}\]


\[\frac{3p}{p(p+3)}+\frac{4p+12}{p(p+3)}\]


\[\frac{3p+4p+12}{p(p+3)}\]


\[\frac{7p+12}{p(p+3)}\]


\[\frac{7p+12}{p^2+3p}\]


So \[\frac{3}{p+3}+\frac{4}{p}=\frac{7p+12}{p^2+3p}\]