Question

f(x)= x^2+ 4x-4

Answer 1

using the discriminant, determine the nature of the zeros of each function .

Answer 2

use
\[b^2-4ac\] with
\[a=1,b=4,c=-4\] get
\[16+16=32\] so since the discriminant is positive it has two zeros. now we can find them

Answer 3

put
\[x^2+4x-4=0\]
\[x^2+4x=4\]
\[(x+2)^2=4+2^2=8\]
\[x+2=\pm\sqrt{8}=2\sqrt{2}\]
\[x=2\pm\sqrt{2}\]

Answer 4

so your two zeros are
\[\{2-\sqrt{2},2+\sqrt{2}\}\]

Answer 5

nice! thanks for helping me! .. ^^ ..

Answer 6

yw

Answer 7

f(x)= x^2 + 2x + 13,by using the discriminant, determine the nature of the zeros of each function ..