Question

i was saloving for a quadratice equation and i got down to the numerator equal to -b+-8 and the denominator as 2, how do i simplify

Answer 1

you have to leave it as it is

Answer 2

do you have a value for b?

Answer 3

in order to help we would do better to see your original equation

Answer 4

b=2

Answer 5

ok so the answer is either -5 or 3

Answer 6

x^2+2x-15=0

Answer 7

so the coefficients are 1, 2 and -15

Answer 8

yes

Answer 9

now lets see if your work thru is good:

\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
\[\frac{-2\pm\sqrt{2^2-4(1)(-15)}}{2(1)}\]
\[\frac{-2\pm\sqrt{4+60}}{2}\]
\[\frac{-2\pm\sqrt{64}}{2}\]
\[\frac{-2\pm8}{2}\]

Answer 10

yes :)

Answer 11

so you did fine except for you didnt plug in your "2" into that top "b" :)

Answer 12

yes now how do i finish tht problem? divide -1 and 8 by two?

Answer 13

-2 ans 8 sorry

Answer 14

the +- sign means we have 2 equations, its just a compact way to write this:
\[\frac{-2+8}{2}\text{ and }\frac{-2-8}{2}\]
then you can simplify

Answer 15

what is the question exactly?

Answer 16

there are two solutions to the equation

Answer 17

-2+8 = 6 ; 6/2 = 3

-2-8 = -10; -10/2 = -5

Answer 18

thankyou :)

Answer 19

no problem

Answer 20

i find that when I am learning new things, that I have to remember not to forget the old stuff I learned ;)

Answer 21

"remember not to forget" = lol