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Mathematics 21 Online
OpenStudy (anonymous):

Given the center of a circle is at (2,-4) and one of the points on the circle is (5,-8), wat is the length of the diameter of the circle?

OpenStudy (anonymous):

a.12 b.10 c.6 d.5

OpenStudy (anonymous):

Twice the distance between so 10

OpenStudy (anonymous):

how did you get that? I hv the answer key, but hv no idea how to do

OpenStudy (anonymous):

Distance between points is sqrt((2-5)^+(-4-(-8)^2) = 5 = radius so diameter is 2r = 10

OpenStudy (anonymous):

wat equation is that?

OpenStudy (anonymous):

Essentially it's Pythagorus aka the distance formula sqrt((x-x1)^2 + (y-y1)^2) This is a standard formula.

OpenStudy (anonymous):

ahhh. behold the glory of a true master. thank you!

OpenStudy (anonymous):

ur welcome.

OpenStudy (anonymous):

does it matter what is x1 or y1?

OpenStudy (anonymous):

Either way, the signs disappear in the squaring.

OpenStudy (anonymous):

and this equation basically only works in grids? or can it be used for a real life problem?

OpenStudy (anonymous):

In real life u will likely measure the distance with something...:-)

OpenStudy (anonymous):

oop. so only on grids

OpenStudy (anonymous):

Well, the Cartesian Coordinates are what permits the calculation to be made.

OpenStudy (anonymous):

Pythagorus works fine in real life if u have a right angle type problem; But like I said, u are likey to use an instrument, tape measure, laser , whatever...

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