Question

solve by factoring or quadratic formula
x^2-8x+16x=0

Answer 1

This is a perfect square.
The middle number is double the square root of last number.
sqrt(16) = 4
x^2 -8x+16 = (x-4)^2

Answer 2

and then what?

Answer 3

wait is that supposed to be "16x" , didn;t see that

Answer 4

no just 16 sorry

Answer 5

well now its in factored form
(x-4)^2 = 0

solve for x
square root both sides

Answer 6

im confused how do u solve tht equation??

Answer 7

im telling you how
Take square root of both sides
what do you get?

Answer 8

i dont know?

Answer 9

shouldnt the factored form be like (x+4)(x+4)

Answer 10

yes that is another way of writing it, except it should be (x-4)(x-4)

Answer 11

so then whats the next step after (x-4)(x-4)

Answer 12

find a x value that makes (x-4) = 0
x-4 = 0
solve for x

Answer 13

x=4

Answer 14

btw
\[\sqrt{(x-4)^{2}} = x-4\]
that is important to know
the square root always cancels out the square

Answer 15

yes
answer is x=4

Answer 16

thanks

Answer 17

your welcome