3/4-1/3x=1/4, solve for x? WHAT!?!?! Help, while explaining how to do it. please. :)
subtract 3/4 from both sides. Then multiply both sides by -3
polpak wht did u deleted my anser
so that would mean, -1/3x = -1/2?
Right so far.
\[\frac{3}{4}-\frac{1}{3}x=\frac{1}{4}\] \[9-4x=3\] \[-4x=3-9\] \[-4x=-6\] \[x=\frac{-6}{-4}\] \[x=\frac{3}{2}\] Note: in the second step, I multiplied EVERY term by the LCD 12 to clear out the fractions.
I deleted it because it was wrong, and because it wasn't what he asked for Hashir.
Don't post answers only, and be sure that when you're explaining something you actually understand the question.
that ws all giberish to me..
Matt, if you go from what you have and multiply both sides by -3 you should get the answer jim got
but u doesnot have to delete the answer because u doesnot have the rights too
I do actually
okay, got it.
thanks
Basically I cleared out the fractions first which gave me a simple linear equation. I then solved for x as I normally would with any normal equation.
Yep, perfectly legit way to do it.
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