Question

A baseball manager must choose a 9-man batting order from a team of 25 players. How manu possible batting orders are there?

Answer 1

it doesn't say so (?)

Answer 2

\[=\frac{25!}{9!}\]

Answer 3

it a batting order, so yes order matters
use permutations
25P9

Answer 4

oops i messed up, it should be 16! in denominator

Answer 5

\[nPr = \frac{n!}{(n-r)!}\]

Answer 6

25!/16! gives me 741355000000?

Answer 7

yeah its a huge number
thats how many possible lineups there are
crazy huh

Answer 8

wowsers :D

Answer 9

can i ask you another on here or should i start a new thread?

Answer 10

no go ahead

Answer 11

it says: of the first ten questions on a quiz, a student must answer 7. of the second 5 questions a student must answer 3. in how many different ways can this be done?

Answer 12

so......10!/3! x 5!/2!?

Answer 13

yes you have right idea
however in this case order doesn't matter. it doesn't matter which 7 of the 10 they answer
so use combinations
\[nCr = \frac{n!}{r!(n-r)!}\]

Answer 14

whoa

Answer 15

you should end up with 1200

Answer 16

workin it