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Simplify: (4xy^-2)/(12x^-1/3y^-5)
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\[\frac{4xy^{-2}}{\frac{12x^{-1}}{3y^{-5}}}\] is that right?
yep!
Sorry I don't know how to make it look like a real equation
\[4xy^{-2} \div \frac{12x^{-1}}{3y^{-5}}=4xy^{-2} \times \frac{3y^{-5}}{12x^{-1}}\] \[\frac{4xy \cdot 3y^{-5}}{12x^{-1}}=\frac{12xy^{-5+1}}{12x^{-1}}=\frac{xy^{-4}}{x^{-1}}\] \[=\frac{x}{x^{-1}} \cdot \frac{y^{-4}}{1}\] \[=x \cdot x \frac{1}{y^4}=x^2 \frac{1}{y^4}=\frac{x^2}{y^4}\]
Wonderful thank you so much
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np i tried to put in alot of steps so it was easy to follow
Thank you!! :)
4xy^-2/12x^-1/3 y^-5
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