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how can we determine a horizontal asymptote?
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If the degrees of the numerator and denominator are equal, then the horizontal asymptote is y = k where k is the ratio between the leading coefficients of the two (ie k = quotient of leading coefficients). Post a problem so we can walk you through it.
f(x)=(3x^2+2x-4)/(2x^2-x+1)
Degree of numerator = 2 Degree of denominator = 2 So we just divide the leading coefficient of the numerator (3) by the leading coefficient of the denominator (2) to get \[\frac{3}{2}\] So the horizontal asymptote is \[y=\frac{3}{2}\]
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