Question

Simplify: 3(n+1)!/5n!

Answer 1

3/5 n+1

Answer 2

(n+1)! = (n+1) * n!
(3/5)(n+1)

(3n+3)/5

Answer 3

Imran cant be wrong!

Answer 4

Could you include steps for how you got that? I actually wanna know how to do it

Answer 5

it's same answer

Answer 6

(n+1)(n)(n-1)
---------------
n (n-1)

every thing cancel beside n+1

Answer 7

Remember, n! by definition means n! = n*(n-1)*(n-2)*(n-3)...(3)(2)(1)

So (n+1)! = (n+1)(n)(n-1)(n-2)(n-3)...(3)(2)(1)


Notice how n! and (n+1)! have the terms n*(n-1)*(n-2)*(n-3)...(3)(2)(1) in common. So when you divide (n+1)! by n!, these terms will cancel out. This will leave you with n+1


So in math notation, I'm saying that \[\frac{(n+1)!}{n!}=n+1\]


This then means that \[\frac{3(n+1)!}{5n!}=\frac{3(n+1)}{5}=\frac{3n+3}{5}\]

Answer 8

Ohh okay I think i get it. It cancels, cool thanks guys!