Determine the exact value: cos(sin^-1(1/2))
i will draw you a picture
Thanks that'd be great
i always find it useful to draw a right triangle to do these problems
draw a triangle. put one angle as theta say. then using "opposite over hypotenuse" put opposite as 1 and hypotenuse as 2. find that the third side is \[\sqrt{3}\] by pythagoras so \[\cos(\theta)=\frac{\sqrt{3}}{2}\]
do you see how i found the missing side i used the pythagoren thm
thats a beautiful triangle
don't make fun of my triangle
that is method one. method two is to say \[\sin^{-1}(\frac{1}{2})=\frac{\pi}{6}\] and \[\cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}\]
lol
a picture is worth a thousand ships.
That really helps actually. You wouldn't happen to have the full chart handy would you?? I have like 6 more problems with sin/cos/tan
the unit circle?
you can find some pretty unit circles online
yes that's what it's called! i couldn't remember. but i couldn't search it till i knew what it was, so thanks lol
np :)
here is a nice one
got all the stuff. unit circle on last page
i was kidding
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