Question

Solve for a:

(a+3b)/(a-3b) = 10k+3

Answer 1

\[\frac{a+3b}{a-3b}=10k+3\]
\[a+3b=(10k+3)(a-3b)\]
\[a-(10k+3)a=-3b(10k+3)-3b\]
\[(1-(10k+3)a=-30bk-9b-3b\]
\[(-9k-3)a=-30bk-12b\]
\[a=\frac{-30bk-12b}{-9k-3}=\frac{30bk+12b}{9k+3}\]

Answer 2

Thank you. You've become my new best friend haha

Answer 3

can simplify a little by canceling the 3 top and bottom i guess you get
\[a=\frac{10bk+4b}{3k+1}\]

Answer 4

yw (check my algebra it is late)

Answer 5

Thanks for the warning. Final answer was actually [6(5bk+2b)]/[2(5k+1)]