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how do I find the n th term in the following sequence? 1,3,6,10,15,21... a30
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we seem to be doing the same hw :D
an=a1+(n−1)d
isn't that when it is constant?
yeah, i didn't see that....thinking ;/
did you try the geometric sequence formula?
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\[a _{n}=a _{1}r ^{n-1}\] ?
this is 1 1+2 1+2+3 1+2+3+4 1+2+3+4+5
formula is \[\frac{n(n+1)}{2}\]
yes
and so \[a_{30}=\frac{(30)(31)}{2}=15\times 31=465\]
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thank you!!!!!
yw
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