Question

factorise the eq : x^2 - 3x +9/4

Answer 1

notice that its a perfect square?

Answer 2

what two number sum to -3 and multiplies to 9/4

Answer 3

\[(4x ^{2}-6x+9)/4= (2x-3)(2x-3)/4\]

Answer 4

nonononon. the constant c = 9/4. Not the whole thing over 4.

Answer 5

yes it is i multiplied the numerator by 4 as a sort of LCM hope u understood

Answer 6

can't it be solved without using an LCM?

Answer 7

ya

Answer 8

try completeing the square on it :)

Answer 9

its a perfect square, you can'r, and don't need to complete the square!

Answer 10

yes it can be done like dis.....\[x ^{2}-2*(3/2)*x+(3/2)^{2}=(x-3/2)^{?}\]

Answer 11

I asked you again ,
what two number sum to -3 and multiplies to 9/4

Answer 12

since its a perfect square; then just compact it then

Answer 13

-3/2 and -3/2 add up to -3 and product is 9/4

Answer 14

(x + b/2)^2

Answer 15

\[x^2 -3x + \frac{9}{4}\]

Answer 16

so it would be (x-3/2)^2 ?

Yes, thank you agdgdgdgwngo.

Answer 17

so
\[(x-\frac{3}{2})^2\]

Answer 18

4x^2-12x+9=4x^2-6x-6x+9=2x(2x-3)-3(2x-3)=(2x-3)^2

Answer 19

Thank you, imranmeah91.