Question

Hi i need help in solving this derivative of trig. functions ^_^
y=sin(cos x)
y=tan(x sin x)
v=(1+sin^4y)^3/2
r=cos 2θ/1-sin 2θ

Answer 1

those are some rather odd constructs

Answer 2

pls. show your solutions ^_^

Answer 3

cos(x) is a ratio; how do you take the sin of a ratio?

Answer 4

http://www.wolframalpha.com/input/?i=sin%28cosx%29
apparently its only my confusion :)

Answer 5

Yeah, you can just apply the chain rule; consider sin(cos x) to be the same as sin(u), so the derivative is \(\frac{d}{du}sin(u) u'\). Since the derivative of sin(u) is -cos(u) and the derivative of cos(x) is sin(x), we get \(-cos(cos x)\cdot sin(x)\).