Can I say that all orthonormal matrices are symmetric?
symmetric \[A^T=A\] orthomormal \[A^T=A^{-1}\] so no, they are different conditions
Somehow I seem to get almost all othornormal matrices as symmetric ones, which made me think like all othornormal matrices are symmetric.
\[\left[\begin{matrix}\frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\ \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2}\end{matrix}\right]\] is an orthonormal matrix that is not symmetric
oh wow.... so indeed there are orthonormal matrices that aren't symmetric. thanks for your help! :)
\[\left[\begin{matrix}\cos(\theta) & -\sin(\theta) \\ \sin(\theta)& \cos(\theta)\end{matrix}\right]\] here is the rotation matrix about the origin for \[R^2\] it is an orthonormal matrix that is not symmetric for most values of theta.
oh ya.... a rotation matrix is always an othornormal matrix, is this right?
yes
thanks a lot Zarkon! thank you so much!
np
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