Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Can I say that all orthonormal matrices are symmetric?

OpenStudy (anonymous):

symmetric \[A^T=A\] orthomormal \[A^T=A^{-1}\] so no, they are different conditions

OpenStudy (anonymous):

Somehow I seem to get almost all othornormal matrices as symmetric ones, which made me think like all othornormal matrices are symmetric.

OpenStudy (zarkon):

\[\left[\begin{matrix}\frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\ \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2}\end{matrix}\right]\] is an orthonormal matrix that is not symmetric

OpenStudy (anonymous):

oh wow.... so indeed there are orthonormal matrices that aren't symmetric. thanks for your help! :)

OpenStudy (zarkon):

\[\left[\begin{matrix}\cos(\theta) & -\sin(\theta) \\ \sin(\theta)& \cos(\theta)\end{matrix}\right]\] here is the rotation matrix about the origin for \[R^2\] it is an orthonormal matrix that is not symmetric for most values of theta.

OpenStudy (anonymous):

oh ya.... a rotation matrix is always an othornormal matrix, is this right?

OpenStudy (zarkon):

yes

OpenStudy (anonymous):

thanks a lot Zarkon! thank you so much!

OpenStudy (zarkon):

np

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!