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Simplify the following quotient of complex numbers into the form a + bi. 1+8i/-6+i
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1-i/3
multiply up and down with (-6-i)---> (1+8i)*(-6-i)/35=(2-49i)/35
2/37-(49 i)/37 I believe twoof is wrong
okay
pk u have 36-1 not 36+1
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pk51 is correct
don't u have (6-1)*(6+1)=6^2-1^2=36-1=35? :S
no
oops, I solved it like there were no parenthesis
can u explain me pls?
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\[(-6+i)(-6-i)=(-6^2)-i^2=36-(-1)=37\]
righttt Thnx ^_^
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