Question

what are the zeros of the polynomial function f(x)=(x+3)(x-1)(x+5) .....Are they 3, -1, and 5???/

Answer 1

no they are -3,1, and -5

Answer 2

-3,1,-5

Answer 3

x =1,-5,-3

Answer 4

THANK YOU YOU GUYS ROCK

Answer 5

it is zero when you replace x by those numbers. for example if x is -3 you get
\[(-3+3)(-3-1)(-3+5)=0\]

Answer 6

Thanks for explaining !

Answer 7

A zero is what you plug in to a variable to make the equation=0
so (-3+3), (-1+1) or (-5+5) would make that part of the equation=0, so when the rest of it is multiplied out it would still=0

Answer 8

I have another one, f(x) = x^3 - x^2 - 6x?? What are the zeros for this??

Answer 9

factor out an x first

Answer 10

get
\[x(x^2-x-6)\] then factor further as
\[x(x-3)(x+2)\] so zeros are at
\[\{0,-2,3\}\]

Answer 11

-2, 0 and 3

Answer 12

THANK YOU :) I AM A FAN

Answer 13

Glad we could help :)

Answer 14

1 073 741 824 * (4 * 4 * 4 * 4) = 274 877 906 944

Answer 15

i used google and java