Question

Find the polynomial f(x) that has the roots of -3, 5 of multiplicity 2....also how you would verify the zeros

Answer 1

(x+3)(x-5)^2

Answer 2

(x+3)(x-5) = 0
x^2 - 2x - 15 = 0
The zeroes are at x = -3 and x = 5, since these are the roots.
Graph it and you will see.

Hope this helps.
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Answer 3

x^3-7 x^2-5 x+75

Answer 4

This includes multiplicity?

Answer 5

Mine does

Answer 6

How you verify the zeros? By plugging them in?

Answer 7

zeros of f(x)

Answer 8

yeah plug in 3 or 5 you would get 0

Answer 9

the reason I said (x-5)^2 instead of (x-5)
is because of multiplicity

Answer 10

gotcha...

Answer 11

ok so plug 3 or 5 into x

Answer 12

Yes, you should get zero