how to factor a polynomial with a fraction. EX. x^2+7x+11
well , you can do this x(x+7) +11
I think your best bet is to complete the square to solve for vertex or use the quadratic formula because its not factorable
If we have to use a perfect square, how would we do that?
You set it up like this: (x^2 + 7x) + 11 You divide the coefficient of x which is 7 by 2. Square (7/2) and add it to both sides
So now you have (x^2 + 7x + 49/4) -49/4 + 44/4
(x + 7/2)^2 -5/4
Wait but how do you simplify x^2+7x+49/4, because I got up to this point, I dont' get what to do after...
You have to consider what multiply to 49/4 and add up to 7
okay because its an equation whatever you do to the right side must be applied to the left side...if initially you set up your equation equal to 0 then when you added 49/4 you will also add 49/4 to the right side
x^2 + 7x + 49/4 + 11 = 49/4
(x^2 + 7x + 49/4) becomes (x + 7/2)^2
And then you subtract 11 which is 44/4 from 49/4 = 5/4
So you have (x + 7/2)^2 - 5/4 = 0...do you understand it?
Oh! So the middle number is what you add to get and the last part of the equation (49/4) is what you multiply to get.
Yes, that's correct
Thank you you have been very helpful! is there a way I can +1 you or something? I just signed up so I have no clue how this works :S
you can "Good Answer" me
yes that's correct! Glad you understand
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