Question

Are the complex fractions x^2 - x- 20 / 4 / x-5/ 1- and 10/4/x-5/x^2 - x -20 equivalent???? how do i simplify each?

Answer 1

there is something funny here. what is the 1- hanging out at the end?

Answer 2

oh sorry! I mean 10

Answer 3

oh ok

Answer 4

\[\frac{\frac{x^2-x-20}{4}}{\frac{x-5}{10}}\]
like this one?

Answer 5

no the x-1 is x-5

Answer 6

oh sorry, i thought it said x-1

Answer 7

and then divided by the other fraction

Answer 8

ok so first we write
\[\frac{x^2-x-20}{4}\times \frac{10}{x-5}\]
then
\[\frac{(x-5)(x+4)}{4}\times \frac{10}{x-5}\]
then
\[\frac{5(x+4)}{2}\]

Answer 9

Okay :) and then what about teh next fraction?

Answer 10

that one is
\[\frac{10}{4}\times \frac{x^2-x-20}{x+5}\] so i guess they are identical.

Answer 11

okay! wow, thaank you sooooo much satellite :D you're the best.

Answer 12

Sorry, can you just explain why they are?