Question

please help
2- a-10/a+4 = a^2-2/a+4

Answer 1

\[\frac{2 - a -10}{a+4} = \frac{a^2 -2}{a+4} \]

Answer 2

Is that what it looks like?

Answer 3

yes

Answer 4

Okay, well the first thing I would do is try to factor the numerators to see if we can cancel anything

Answer 5

except for 2- then the a-10/a+4= a^2-2/a+4

Answer 6

If there is something that's in parentheses let me know

Answer 7

no, its not in parentheses

Answer 8

so the fraction is correct as written, right?

Answer 9

yes

Answer 10

Okay, hold on

Answer 11

1. Okay, so basically the only thing that simplifies is 2 - a - 10. It simplifies to -a - 8.

2. We will need to cross multiply:

\[\frac{-(a+8)}{a+4}=\frac{a^2-2}{a+4}\]

Answer 12

3. The result of cross multiplying gives us:
\[-(a+8)(a+4)=(a^2-2)(a+4)\]

Answer 13

Now we will have to multiply everything back out. We can't divide both sides by (a+4) because it will eliminate one of the solutions for the variable a

Answer 14

\[-a^2-12a-32 = a^3+4a^2-2a-8\]

Answer 15

Now we will have to move like terms on one side:

Answer 16

Put the variables on one side and put the last coefficients on the other side

Answer 17

\[a^3 +3a^2 +10a = -24\]

Answer 18

this is still somewhat confusing to me, but I am trying to understand it more

Answer 19

Wait a minute..let me post twiddla. You can post how the problem looks on there

Answer 20

http://www.twiddla.com/solved

Answer 21

Okay, so it all came out to:

\[a^2 - a - 20\]

(a-5)(a+4)

Answer 22

So the solution is a = 5, -4

Answer 23

so -4 is the other solution for a

Answer 24

lost connection to to other

Answer 25

That's okay