Question

can any body show me how to express this in simplest form?
x^2+9x+14/x^2-49 \[\div\] 3x+6/x^2+x-56

Answer 1

we need to factor as much as possible

Answer 2

okay

Answer 3

by factoring you mean?

Answer 4

x^2+9x+14 factors to (x+2)(x+7)

Answer 5

okay i get it

Answer 6

x^2-49 factors to (x-7)(x+7)

Answer 7

((x+2)(x+7))/((x-7)(x+7)) * (x-7)(x+8)/(3x+6)

Answer 8

DONE!

Answer 9

3x+6 factors to 3(x+2)

Answer 10

x^2+x-56 factors to (x-7)(x+8)

Answer 11

okay

Answer 12

x^2+9x+14/x^2-49 = (x+2)/(x-7)
3x+6/x^2+x-56 = (3 (x+2))/((x-7) (x+8))
(x+2)/(x-7) * ((x-7) (x+8))/(3 (x+2))
(x+8)/3

Answer 13

thats the simplified answer pk51?

Answer 14

Yes, do you understand how I got it?

Answer 15

so you factored both equations? then divided?

Answer 16

Yes, but when dividing fractions, you flip one and the multiply across.

Answer 17

no multiplied

Answer 18

ohhhh!!!! okay i got it