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Integration with a trigonometric function
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what is the question ?
\[\int\limits_{0}^{pi/4}(\tan^2x)dt = \]
tan^2?
You have to wait for it to convert to the equation style... its tangent squared x
does it say how it wants to solve it?
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I'm assuming by integrating and using F(b) - F(a) but I don't know how to use the chain rule with integration
alright you ned to use an identity \[Cos^2x + Sin^2x = 1\] deriving from that yuo get \[1+Tan^2x=Sec^2x\]
does this help?
solve for tan^2x and then you'll get something that you can integrate
got it
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