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Mathematics 9 Online
OpenStudy (anonymous):

Integration with a trigonometric function

OpenStudy (anonymous):

what is the question ?

OpenStudy (anonymous):

\[\int\limits_{0}^{pi/4}(\tan^2x)dt = \]

OpenStudy (anonymous):

tan^2?

OpenStudy (anonymous):

You have to wait for it to convert to the equation style... its tangent squared x

OpenStudy (anonymous):

does it say how it wants to solve it?

OpenStudy (anonymous):

I'm assuming by integrating and using F(b) - F(a) but I don't know how to use the chain rule with integration

OpenStudy (anonymous):

alright you ned to use an identity \[Cos^2x + Sin^2x = 1\] deriving from that yuo get \[1+Tan^2x=Sec^2x\]

OpenStudy (anonymous):

does this help?

OpenStudy (anonymous):

solve for tan^2x and then you'll get something that you can integrate

OpenStudy (anonymous):

got it

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