If n is a known positive integer, for what value of k is ... (see equation)
k = constant.
\[\int\limits_{1}^{k}x^n-1 dxugh it is = 1/n\] ugh it is supposed to be x^(n-1)
Shall we work on this together?
sure
\[\int\limits_{1}^{k}(x^n-1)dx = 1/n?\]
so if I understand correctly you're integrating from 1 to k for x to the power of n-1 with respect to x, and that is equal to 1/n, is that correct?
yes!
okay, so let's evaluate the integral on the left side, it should be (1/n)*x^n, from 1 to k right?
yes. and that is as far as I got.
okay so we can divide out the 1/n from both sides, so now we have x^n from 1 to k is equal to 1, with me so far?
yep
okay so let's evaluate the integral of x^n from 1 to k, this equals k^n - 1^n
1^n is just 1, so let's add 1 to both sides, now we have k^n = 2, so k is equal to the nth root of 2
thanks!
Since n has to be a positive integer, the only n that works is 1, which means k = 2
the answer choices only go as far as the previous step
Join our real-time social learning platform and learn together with your friends!