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Mathematics 16 Online
OpenStudy (anonymous):

If n is a known positive integer, for what value of k is ... (see equation)

OpenStudy (saifoo.khan):

k = constant.

OpenStudy (anonymous):

\[\int\limits_{1}^{k}x^n-1 dxugh it is = 1/n\] ugh it is supposed to be x^(n-1)

OpenStudy (anonymous):

Shall we work on this together?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

\[\int\limits_{1}^{k}(x^n-1)dx = 1/n?\]

OpenStudy (anonymous):

so if I understand correctly you're integrating from 1 to k for x to the power of n-1 with respect to x, and that is equal to 1/n, is that correct?

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

okay, so let's evaluate the integral on the left side, it should be (1/n)*x^n, from 1 to k right?

OpenStudy (anonymous):

yes. and that is as far as I got.

OpenStudy (anonymous):

okay so we can divide out the 1/n from both sides, so now we have x^n from 1 to k is equal to 1, with me so far?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

okay so let's evaluate the integral of x^n from 1 to k, this equals k^n - 1^n

OpenStudy (anonymous):

1^n is just 1, so let's add 1 to both sides, now we have k^n = 2, so k is equal to the nth root of 2

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

Since n has to be a positive integer, the only n that works is 1, which means k = 2

OpenStudy (anonymous):

the answer choices only go as far as the previous step

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