Mathematics
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OpenStudy (anonymous):
integration.. im guessing its harder than i think it is...
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OpenStudy (anonymous):
OpenStudy (anonymous):
alright you f''(x) = your acceleration
OpenStudy (angela210793):
these r easy Sptsam..all u have to do is remember the formulas
OpenStudy (anonymous):
integration is not hard...but you have to do a lot of them for practice to get the hang of it
OpenStudy (anonymous):
f'(x) = velocity
f(x)=s(t)
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OpenStudy (anonymous):
alright lemme try em
OpenStudy (anonymous):
there's also no integration in this problem
OpenStudy (anonymous):
ya.. wasnt sure bout it cuz its stuck in an integration packet
OpenStudy (anonymous):
yes there is?
OpenStudy (anonymous):
they are giving acceleration, you must integrate to get velocity
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OpenStudy (anonymous):
then solve velocity for t=1, and then integrate again to get s(t) in which you solve for those times
OpenStudy (anonymous):
alright.. sorry u lost me
OpenStudy (anonymous):
f''(x) is your acceleration function, am i right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
they are giving you f''(x) = 8-6t
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OpenStudy (anonymous):
and wanting you to solve s(4)-s(2) which would s(t) would be your position function
OpenStudy (anonymous):
k so find antiderivitive to get s(t)?
OpenStudy (anonymous):
you have to find your velocity equation first so yes you want to integrate it once for now
OpenStudy (anonymous):
what values do i use to define the limits
OpenStudy (anonymous):
did you integrate it?
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OpenStudy (anonymous):
ya... i think
OpenStudy (anonymous):
that is your v(t) now, you must solve it for v=25 at t=1
OpenStudy (anonymous):
... lost again i got 8t-3t^2
OpenStudy (anonymous):
and they give you v(1)=25
OpenStudy (anonymous):
why would i use that if i could just integrate another time then plug in 2 nd 4
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OpenStudy (anonymous):
because you are missing the constant i believe, it's been a long time since i've done this
OpenStudy (anonymous):
oh..i should review that in my book.. i think i know what ur talking about..
OpenStudy (anonymous):
thanks anyways!
OpenStudy (anonymous):
look at that it explains most of the time they usually say like v(0)=something
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OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
so you should get 25=8(1)-3(1) + C
OpenStudy (anonymous):
20 = C
OpenStudy (anonymous):
then you integrate what you got + 20 and that will get you your position function, then plug and play
OpenStudy (anonymous):
your answer is going to be 32
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OpenStudy (anonymous):
idk if you are still here but i could upload my work if you'd like
OpenStudy (anonymous):
32! yay i got it!
OpenStudy (anonymous):
haha nvm2