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Mathematics 7 Online
OpenStudy (anonymous):

integration.. im guessing its harder than i think it is...

OpenStudy (anonymous):

OpenStudy (anonymous):

alright you f''(x) = your acceleration

OpenStudy (angela210793):

these r easy Sptsam..all u have to do is remember the formulas

OpenStudy (anonymous):

integration is not hard...but you have to do a lot of them for practice to get the hang of it

OpenStudy (anonymous):

f'(x) = velocity f(x)=s(t)

OpenStudy (anonymous):

alright lemme try em

OpenStudy (anonymous):

there's also no integration in this problem

OpenStudy (anonymous):

ya.. wasnt sure bout it cuz its stuck in an integration packet

OpenStudy (anonymous):

yes there is?

OpenStudy (anonymous):

they are giving acceleration, you must integrate to get velocity

OpenStudy (anonymous):

then solve velocity for t=1, and then integrate again to get s(t) in which you solve for those times

OpenStudy (anonymous):

alright.. sorry u lost me

OpenStudy (anonymous):

f''(x) is your acceleration function, am i right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

they are giving you f''(x) = 8-6t

OpenStudy (anonymous):

and wanting you to solve s(4)-s(2) which would s(t) would be your position function

OpenStudy (anonymous):

k so find antiderivitive to get s(t)?

OpenStudy (anonymous):

you have to find your velocity equation first so yes you want to integrate it once for now

OpenStudy (anonymous):

what values do i use to define the limits

OpenStudy (anonymous):

did you integrate it?

OpenStudy (anonymous):

ya... i think

OpenStudy (anonymous):

that is your v(t) now, you must solve it for v=25 at t=1

OpenStudy (anonymous):

... lost again i got 8t-3t^2

OpenStudy (anonymous):

and they give you v(1)=25

OpenStudy (anonymous):

why would i use that if i could just integrate another time then plug in 2 nd 4

OpenStudy (anonymous):

because you are missing the constant i believe, it's been a long time since i've done this

OpenStudy (anonymous):

oh..i should review that in my book.. i think i know what ur talking about..

OpenStudy (anonymous):

thanks anyways!

OpenStudy (anonymous):

look at that it explains most of the time they usually say like v(0)=something

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

so you should get 25=8(1)-3(1) + C

OpenStudy (anonymous):

20 = C

OpenStudy (anonymous):

then you integrate what you got + 20 and that will get you your position function, then plug and play

OpenStudy (anonymous):

your answer is going to be 32

OpenStudy (anonymous):

idk if you are still here but i could upload my work if you'd like

OpenStudy (anonymous):

32! yay i got it!

OpenStudy (anonymous):

haha nvm2

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