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Mathematics 15 Online
OpenStudy (anonymous):

what is the least integer n such that 1/2n <0.001?

OpenStudy (anonymous):

is it 501

OpenStudy (anonymous):

can you explain your breakdown please

OpenStudy (anonymous):

i just thought that 1/1000 is 0.001 so 2n should be greater than 1000

OpenStudy (anonymous):

ok i see where you comin from..u used logic..thanx..

OpenStudy (anonymous):

the answer choices were 10..11..500..501

OpenStudy (anonymous):

thanx

OpenStudy (anonymous):

that's how'd you show it without logic

OpenStudy (anonymous):

it shud be n>500

OpenStudy (anonymous):

ur the best lots of thanx

OpenStudy (anonymous):

k just goes to show that i have not studied inequalities properly

OpenStudy (anonymous):

battle of the brains please breakdown..so set it up as a inequality equ?

OpenStudy (anonymous):

cool

OpenStudy (anonymous):

and problemsolver you are correct also, only you are finding the values at which 1/2n is > the value . either way works i believe

OpenStudy (anonymous):

well at the point where I have n<1/500 i understand..but how do I solve

OpenStudy (anonymous):

with the given answers 10 11 500 501

OpenStudy (anonymous):

have u studied inequaliteis

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

is the < have an =

OpenStudy (anonymous):

because that makes a big difference

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so bascially n=or <1/500..i get it..so as long as the 1/2n is less than .001 im good right??

OpenStudy (anonymous):

ohhhhhhhhhhhhhhh I got u...mucho gracious

OpenStudy (anonymous):

the ques is what is the least integer n such that 1/2n<.001

OpenStudy (anonymous):

it's 501 and it would be greater than.... it's just late here

OpenStudy (anonymous):

sorry bout that..im n new york..but thanks a lot you def helped

OpenStudy (anonymous):

alright bed time but here you go 1/2n <1/1000 1000(2n)/2n<1000/1000(2n) 1000<2n 500<n or n>500

OpenStudy (anonymous):

i kept thinking that the n was in the numerator

OpenStudy (anonymous):

in otherwords i'm just taking the reciprocal of both sides to get the n out of the denominator.

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