Mathematics
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OpenStudy (anonymous):
How do you find the cube roots of -64?
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OpenStudy (lalaly):
-4
OpenStudy (saifoo.khan):
Ninj'ad
OpenStudy (saifoo.khan):
damn!
OpenStudy (anonymous):
make it an imaginary number first
OpenStudy (angela210793):
no just -4
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OpenStudy (lalaly):
-4*-4*-4=-64
OpenStudy (anonymous):
actually nvm its a cube root
OpenStudy (anonymous):
u dont need to saifoo stop confusing me
OpenStudy (angela210793):
yea so u can have negative no.s under it :)
OpenStudy (saifoo.khan):
\[\Huge -4\]
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OpenStudy (saifoo.khan):
lol. My bad. :(
OpenStudy (anonymous):
hi angela
OpenStudy (anonymous):
i would write that as 4i
OpenStudy (angela210793):
@Hahd Hi!
OpenStudy (anonymous):
zbay -64i thats what you get with 4i
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OpenStudy (anonymous):
keep it -4
OpenStudy (saifoo.khan):
\[\Huge \color\red {-4}\]
OpenStudy (anonymous):
\[\color{salmon}{\huge{\checkmark}}\]
OpenStudy (anonymous):
actually there should be 3 roots -4 is only one of them???
OpenStudy (angela210793):
3 roots? O.o
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OpenStudy (anonymous):
cube roots of -64???
OpenStudy (anonymous):
there are no roots its not an equation someone's sleepy
OpenStudy (saifoo.khan):
\[\Huge \color\green \blacksquare\]
OpenStudy (nilankshi):
this is rite
OpenStudy (saifoo.khan):
\[\Huge \color\yellow \blacksquare\]
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OpenStudy (saifoo.khan):
this one matches! :)
OpenStudy (angela210793):
Saif....teach me tht...
OpenStudy (anonymous):
x^3 = -64
x^3 + 64 = 0
(x + 4)(x^2 + 16 -4x) = 0
x = -4
x^2 + 16 -4x=0
\[x = \frac{4 \pm \sqrt{16 - 64}}{2}\]
OpenStudy (anonymous):
now solve them
OpenStudy (anonymous):
you will get your three
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OpenStudy (saifoo.khan):
angela, check your facebook.
OpenStudy (anonymous):
thanksss
OpenStudy (anonymous):
ishaan i hate to poinnt it out but ur b value is wrong
OpenStudy (saifoo.khan):
how about this?
\[\Huge \bigodot\]
OpenStudy (saifoo.khan):
Punch here^
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OpenStudy (anonymous):
are you sure hahd ?
OpenStudy (anonymous):
u put the constant
OpenStudy (anonymous):
oh nvm
OpenStudy (anonymous):
check that again hahd I am sure it's not like that
OpenStudy (anonymous):
lol its 7 in the morning
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
real answer would be -4
OpenStudy (anonymous):
ready to be sensei today imran
good morning : )
OpenStudy (anonymous):
but there are three roots so two additional roots
are 4(cos 60+ i sin 60)
\[2+i\sqrt{3}\]
and its conjugate
\[2-i\sqrt{3}\]
OpenStudy (anonymous):
morning ishaan