A tool box has a volume of x3 + 8x2 + 11x – 20 cm3 and the height is x + 5 cm. Find the polynomial that would represent the area of the bottom of the tool box? Explain your reasoning.
your real job is to divide \[\frac{x^3+8x^2+11x-20}{x+5}\] i would use synthetic division,but you can do it with long division
you will get \[x^2+3x-4\] do you need the steps?
Yes please
do you know how to use synthetic division?
synthetic division may be easier, but i think it's bad for the environment :)
it is a better environment for synthetic than long division. i can write the process but if you don't know it you will not understand it
No, can you show me how you would do it?
list the coefficients of \[x^3+8x^2+11x-20\] they are 1 8 11 -20
because you are dividing by x + 5 put -5 on the side 1 8 11 -20 -5 _______________________________
bring down the 1 1 8 11 -20 -5 _______________________________ 1
1*-5=-5 1 8 11 -20 -5 -5 _______________________________ 1
8 - 5 = 3 1 8 11 -20 -5 -5 _______________________________ 1 3
3*-5=-15 1 8 11 -20 -5 -5 -15 _______________________________ 1 3
11 - 15 = -4 1 8 11 -20 -5 -5 -15 _______________________________ 1 3 -4
-5 * -4 = 20 1 8 11 -20 -5 -5 -15 20 _______________________________ 1 3 -4
-20 + 20 = 0 1 8 11 -20 -5 -5 -15 20 _______________________________ 1 3 -4 0
your solution is the bottom row. it is \[x^2+3x-4\]
so what hapened to the last part? explain ur reasoning?
Join our real-time social learning platform and learn together with your friends!