what is the distance betwen the points (8,3) and (2,0), using the distance formula?
\[d = \sqrt{(x_2-x_1)^2+(y_2 - y_2)^2}\]
@Gir_le Use the above formula.
If you know the pythagorean theorem, you never need to memorize the distance formula because they are the same thing. Look at the attached picture for reference. You can draw a right triangle and then figure out the length of the hypotenuse from the length of the legs.
@smooth math- Can you use the pythagorean theory method if you don't have a graph for the points?
Yes you can. You just need to figure out the legs of the triangle, but one leg is the difference in x and the other leg is the difference in y.
The graph just helps you to see why it works.
can you show me useing these two points, please?
I'll use two different points so you can see how it's done and do the problem on your own.
kk, tx!
Consider the point (2,6) and (5, 10). Okay, well there is a triangle and we want to find the hypotenuse. One leg is the difference in the xs of the points. One has x 5 and the other has x 2, so the difference is 5-2 = 3. The other leg is the difference in y, which is 10 -6 = 4. By the pythagorean theorem, if the hypotenuse is c and the legs are a and b, then c^2 =a^2 +b^2 Which means c = sqrt(a^2 + b^2) a and b are 3 and 4, so c = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5
Understand?
yeah... i had to read that a couple hundred times to get it but i uinderstand now. thanks! :)
Haha sorry I couldn't explain it more simply, but thank you for putting in the effort to understand it =) Good job.
Join our real-time social learning platform and learn together with your friends!