Question

(sqrtx-2)(-2)=x

Answer 1

\[\sqrt{x-2}-2=x\]

Answer 2

If that's what it is, your notation is wrong in the original one

Answer 3

should've been sqrt(x-2) - 2 = x

Answer 4

\[\sqrt{x-2}=x \div(-2)\]
x-2=x^2/4
4x-8=x^2
x^2-4x+8=0

Answer 5

i know thats why i rewrote it because i messed up, sorry :)

Answer 6

Nick Black it's x - 2 not x/2

Answer 7

\[\sqrt{x-2}^{2}=(x+2)^{2}\]
\[x-2=x ^{2}+2x+4\]
-x^2 -x -6 = 0
x^2 +x+6 =0

Answer 8

it can't be finish with factor so you may use
x=(-b+_b^2-4ac)/2a