Question

quadratic equation has one solution x=6 and x=-8 what is the equation found to be?

Answer 1

x - 6

Answer 2

x-8

Answer 3

x+8

Answer 4

sorry

Answer 5

(x-6)(x+8)=0

Answer 6

Add the solutions:
6+(-8) = -2
Multiply the solutions:
6*(-8) = -48

answer:
\[x^2-(-2)x-48 = x^2+2x-48\]

Answer 7

nice, joe

Answer 8

If 'a' is the sum of the roots, and 'b' is the product of the roots, then the equation is:
\[x^2-ax+b\]

Answer 9

(only for quadratic equations)

Answer 10

can you expand that to higher degrees, joe? :)

Answer 11

if the degree's are higher, then you have to multiply the roots k at at time and sum them. For a polynomial:
\[x^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+\ldots+a_1x+a_0\]

If the roots are:
\[r_1,r_2,\ldots, r_n\]

Then \[a_{n-k}\] is the sum of the products of the roots taken k at a time.

Answer 12

Jahtoday how is your finger ?

Answer 13

lol im using 1 hand cuz im icing it

Answer 14

:) nicely stated joe!

Answer 15

im forgetting something....oh, (-1)^k is there as well,

Answer 16

and thank you :)

Answer 17

lol that is pretty nicely done