Please help with this problem.....2x-6 over x-1?? Its a fraction and the answer is 2 I just am lost on how to get there?
are you trying to solve\[\frac{2x-6}{x-1}=2\]
yes
well the 2 doesnt show up, my teacher told me thaths the answer. I have to find the common denominator and all that?
hmmm...then i;m lost. let's start from the beginning.
what is the original problem?
ok thank you I will. what sign do you use for a fraction? on here?
i use the equation editor button...but you can also use parentheses to group the parts of the fraction together
such as 2x-(6/x-1) would be\[2x-\frac{6}{x-1}\]
ok so , (2x-6)/(x-1) - (4)/(1-x)
ahhh..ok. i see now.
sorry that took a while
\[\frac{2x-6}{x-1}-\frac{4}{1-x}\]?
yess yess
:D ok...here goes
:) lets see it!
you understand that x-1 = -1(1-x), right?
yes I got that
ok...so i'm going to change the second fraction so that the denominator looks like the first fraction. (get a common denominator)
ok which is x/1
\[\frac{2x-6}{x-1}-\frac{4}{1-x}=\frac{2x-6}{x-1}-\frac{4}{-(x-1)}\]
good so far?
yes except, when u have to divide by the -1 you only do the denominator?
it doesn't matter...i can put the negative on top, bottom, or out in front.
ok got that then, next step is where I get lost
In fact, I'm going to move it out in front which gives me me minus a negative...which is addition, right?
so we have\[\frac{2x-6}{x-1}-(-\frac{4}{x-1}) = \frac{2x-6}{x-1}+\frac{4}{x-1}\]
ok so now its addition, got it
\[=\frac{2x-6+4}{x-1}\]
since the denominators are the same...right?
yes right
\[=\frac{2x-2}{x-1}=\frac{2(x-1)}{x-1}=2\]
and as they say in the army..."HOOAH! :)
yes right
how do you get the 2(x-1)/(x-1)? Andd yess HOOAH!
but as we in the Navy say to our army brothers..."Hooah, Shipmate!"
i factored out a 2 from both terms in the numerator...
it's distribution in reverse.
2(x-1) = 2x-2, right?
ohh ok thank you life saver :) got it! Nicee Navy/army lingo
my pleasure. :)
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