Radical equation
frac{8}{x(x-2} + frac{2}{x}= frac{4x}{x-2}

Question

Radical equation
  frac{8}{x(x-2} + frac{2}{x}= frac{4x}{x-2}

anonymous · Answer

$$  \frac {8}{x(x-2} + \frac{2}{x}= \frac{4x}{x-2}$$

hero · Answer

Multiply both sides by $$x^2 -2x$$

hero · Answer

That will get rid of the denominator

hero · Answer

$$8x^2 - 16x + 2x^2 - 4x = 4x^3-8x^2$$

hero · Answer

$$4x^3-18x^2+20x = 0$$$$2x(2x^2-9x+10)=0$$

anonymous · Answer

Is that how to check it?

hero · Answer

No, we're finding x

anonymous · Answer

oh. oops.

hero · Answer

What did you do?

anonymous · Answer

I'm just trying to follow what you're saying.

hero · Answer

x = 0 is one of the solutions

anonymous · Answer

ok

anonymous · Answer

How do I find the second solution

hero · Answer

$$2x^2-4x-5x +10 = 0$$$$2x(x-2)-5(x-2) = 0$$$$(x-2)(2x-5)=0$$

hero · Answer

$$x = 2, x = \frac{5}{2}$$

hero · Answer

If you really want to know how I solved all of that you can come to twiddla

hero · Answer

http://www.twiddla.com/solved

anonymous · Answer

I'll have to check it out soon. thanks

hero · Answer

Well, I won't be around long

hero · Answer

It's a live classroom and I have my own domain. So I can't just post the answer unless you're there to witness. Because other students will visit that domain later on, so I'll have to erase it soon. But if you're not going to be there right now, there's no point in posting it.