Question

find the equation of a line that has an x intercept of 5 and passes through the point (2, -1) then tell me how you did it.

Answer 1

m=(y2-y1)/(x2-x1)
m=1/3

Answer 2

find y intercept now

Answer 3

after you have the slope you can use y-y1=m(x-x1) and get your line equation

Answer 4

how did you find slope with only one point?

Answer 5

unless (5, 0) is a point?

Answer 6

when x=0 u get yint hence 1/3=(yi+1)/(0-2)

Answer 7

0, 5 is also a point

Answer 8

lol

Answer 9

how did you get 1/3 then :P? What two points did you use?

Answer 10

solve for yi u get -5/3
plug it into original equation y=1/3x-5/3

Answer 11

i used (0+1)/(5-2)

Answer 12

0.o?

Answer 13

do u follow?

Answer 14

oh I kind of see.

Answer 15

how did you know that (5 -2) would work?

Answer 16

umm (y2-y1)/(x2-x1) is equation correct?

Answer 17

yup.

Answer 18

we have two point in the form (x,y)
(5,0) and (2,-1)

Answer 19

right?

Answer 20

okay. now that I recognize (5,0) as a point this is easy.

Answer 21

>.< thank you.

Answer 22

it's not letting me give you a medal, one sec.

Answer 23

lol