find the sum of the series 13 + 24 + 35 + ... + 156
First, we need to determine how each element of the series changes compared to the previous one. If there is a constant change between elements, then our job is pretty easy
Let's represent our series in variables
yeh its 11
i really dont understand how to use the finite arithmetic formula
Nice, so you know that 11 is being added each time, so you can determine the number of elements in the series by \[(156-13)/(d)\]
where d is constant difference, which you found to be 11
Are you saying you want represent this in sigma notation?
so what do i need to use the Sn = n/2 (A1 + An) for?
So you understand what the formula means?
n= the nth term and A1= 1st term but whats the S?
The sum of the first n elements of the series is equal to the number of the elements divided by 2 * (the first element + the nth element you are considering)
S is for "sum"
So you need to find "n," what element number 156 is in the series
and 156 = A13?
It's actually the 13th element after the 1st one, so it's element 14, A14
oh
Yeah, basically, with (156-13)/d you are figuring out how many times you need to add 11 to 13 in order to get 156, you have to add it 13 times, so there are 13 elements after 13...
aww dang i thought there was a formula to try and figure that out:/
well, looks like it would \[(An - A1)/d+1\]
so whats An?
that is the \[n^{th}\] element in the series
so if im trying to find the 4th term i just plug it in there?
It used here too: Sn = n/2 (A1 + An) ;)
What do you mean by trying to find the 4th term? That equation is for finding how many elements are in the series up the nth element you are considering
oh im dumb i was definitely looking at the wrong problem... i see why i was soo confused
Oh, heh, you got it then?
yehh thanks!!!!
Thanks, no problem!
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