Question

log_{8} 14^{x-1} =13

Answer 1

Rewrite in exponential form
\[14^{x-1} = 8^{13}\]
take log of both sides
\[x-1 = \frac{\log 8^{13}}{\log 14}\]

Answer 2

and the answer is?

Answer 3

\[\log_{8}14^{x-1} = 13\]\[(x-1)\log_{8}14 = 13\]\[x - 1 = 13 / \log_{8}14\]\[x = 1 + 13/\log_{8}14\]

Answer 4

use your calculator...