The base of a log function is never a negative number, right?

Question

anonymous · Answer

Can someone also give me one more example and show me how to solve it? I just really want to make sure I am getting this. Thanks!

anonymous · Answer

No Real Solutions, you only have -bases in the complex plane

anonymous · Answer

right 
if the base was negative it would mean you would have some mess like 
$$(-2)^x$$ which would create all kinds of problems

anonymous · Answer

Okay! Can you show me just one more example to make sure I am getting it?

anonymous · Answer

You change the equation to b^y =x and then plug it in and then solve?

anonymous · Answer

like 
$$\log_2(\frac{1}{8})=?$$ for example?

anonymous · Answer

or 
$$\log(.0001)=?$$ or 
$$log_3(x)=5$$ solve for x

anonymous · Answer

Wait how would you do the fraction one? Yeah I don't get how you would transform them into the other equation.

anonymous · Answer

Sorry, it's like I don't see your replies till way later.