Let R(t) represent the rate at which water is leaking out of a tank, where t is measured in hours. What expression represents the total amount of water that leaks out in the first three hours?
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OpenStudy (anonymous):
where is the equation?
OpenStudy (anonymous):
OpenStudy (anonymous):
sounds like related rates
OpenStudy (anonymous):
well, we can begin by writing this: dV/dt = R(t), as the function represents the differential amount of time, or the rate at which the time is changing
OpenStudy (anonymous):
* rate at which the volume is changing
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OpenStudy (anonymous):
now, since dt can be rearragned in the equation, if i am not mistaken, and we can now write our previouse rate as: dV = R(t)*dt
OpenStudy (anonymous):
Well I think it's either C or D, but I'm not sure about the prime
OpenStudy (anonymous):
50/50, i would pick C
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
call it a hunch
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OpenStudy (anonymous):
ok. Kind of makes sense because if dV is R(t) dt, then it would just be that on the interval 0 to 3, I guess