In how many ways can the letters of the word number be arranged if the N is somewhere to the left of U?
what is the word?
sorry lol i thought i put it in. number
oh wait i did lol
oh wow i didnt see it at all lol
ok i know its 24 x 15 but im not sure about the method i did i think theres an easier way
where is the word?
number
i probably should have caps locked it lol
oh number lol!!!
yeah u got it:)
First i would find out how many ways you can place the N and the U with the N to the left of U. Thats going to be: \[\left(\begin{matrix}6 \\ 2\end{matrix}\right) = 15\]
oh wait we can use a formula it ends up being 6!/2! right
Then i would look at the other four letters, and ask myself how many ways can i rearrange those letters. That would be 4! = 24 So 24*15 is the total number of ways you could rearrange the letters with those requirements.
\[\left(\begin{matrix}n \\ k\end{matrix}\right) = \frac{n!}{k!(n-k)!}\]
so: \[\left(\begin{matrix}6 \\ 2\end{matrix}\right) = \frac{6!}{2!(6-2)!} = \frac{6*5}{1*2} = 15\]
Master joe deserves to be one lol
and another one :)
hey akshay!
hey joe where have you been?
asleep when im supposed to be lolol
oh i am missing you Sir!!!!!!!! Can you see i have reached level 47?
nice nice! *tear* the kids, they grow so fast these days lolol jk
lol
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