Question

number 6... attached

Answer 1

need that one too lol

Answer 2

and 5

Answer 3

sptsam: do you have many left?

Answer 4

The answer is e, do you want an explanation?

Answer 5

please. someone lese on this site told me it was C but never explained it.

Answer 6

um i have like 4

Answer 7

This question involves part one of the fundamental theorem of calculus -- and a chain rule. the answer is almost C but they forgot the chain rule on the second part, if you chain rule the second part it brings a 2x out front so you get

3x^2sin(x^6)-2xsin(x^2)

Answer 8

So you have to first take the derivative and then plug in?

Answer 9

? wait what? isn't it the second fundamental theorem of calculus

Answer 10

so would't it be 1?

Answer 11

i mean A

Answer 12

....

Answer 13

Sorry!!! the answer is C!!!

Let me explain!!!

Answer 14

No you use part one of the fundamental theorem of calculus, so you plug in the values directly into the equation and take the difference, so you have:

sin((x^3)^2)-sin(x^2)

BUT you have a chain rule, so you must add the derivative of x^3 to the first part
and derivative of x to the second part..

giving you

3x^2sin(x^6)-sin(x^2)

Answer 15

let me know if you need more clarification lol.. sorry that i threw you off in the beginning..

Answer 16

Part one of the FTOC looks like this:
\[\int\limits_{a}^{b} f(x) = [f(a)*(d/dx)a] - [f(b)*(d/dx)b]\]

Answer 17

Hopefully that clears things up

Answer 18

what about the d/dx before the integral?