Question

(1.) are these functions invertible? if no, say why not, if yes, find the inverse functions.
(A.) f(x)=x^3 (B.)h(x)=ln x (C.) t(x)=2x (D.) g(t)=cos t (0degrees 14 years ago

Answer 1

A fx=x^3
y=x^3
so the inverse is y=x^1/3 so it is invertible

Answer 2

joe

Answer 3

yes?

Answer 4

please help him further..:P

Answer 5

lol <.<

Answer 6

h(x) = ln(x) is invertible if you restrict the domain.

Answer 7

B h(x)=lnx
y=lnx
therefore inverse is y=e^x true only in its domain

Answer 8

t(x) = 2x is invertible no matter what.

Answer 9

and then cos(t), with 0<t<180 is also invertible.

Answer 10

ya the inverse of t(x) is y=x/2

Answer 11

i am not sure of it joe??? of cost?

Answer 12

procipal domain of cos x is?

Answer 13

*principal

Answer 14

im claim that cos(t) is invertible from 0<t<180 comes from the fact that every value of t will produce a different value of cos(t) in that domain. Its one-to-one (injective).

Answer 15

^ i do recall htta from precal

Answer 16

*that

Answer 17

please help me.

Answer 18

http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e4cb11e0b8b9588049a8c4a

Answer 19

yes right joe then it is invertible..

Answer 20

what is the inverse of g(t) ?

Answer 21

if the domain had been something like 90<t<270, i would say no , its not invertible

Answer 22

the inverse is y=cos^-1(x)

Answer 23

thank you

Answer 24

welcome:)

Answer 25

joe say welcome!! n give me a medal

Answer 26

lol

Answer 27

you slept joe?

Answer 28

im falling asleep >.<

Answer 29

lol i can sense it here!

Answer 30

just 3 more medals then i lvl up >.<

Answer 31

just 3 moer questions then im done with my math packet :D