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can you explain me how to simplify: (A.)log10^(x) (B.) e^(lnx) (C.) ln(e^(2)ln(e ln e)) (D.) e^(2ln A- (ln B)/2) *everything that is raised to a power is in parenthesis :)
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A log10^x=xlog10=x (using log a^b=bloga
wait a sec i will get u reliable help lol
thank you so much!
hi joe
>.>
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sorry for troubling.. just do this one
\[e^{\ln x}= x, \ln e ^{x}, x>0\] by definition
the answer for 2nd one is right.. e^lnx=x.... The property i told you was right too :)
now using the first proprty the answer to the third one is 2
i gotta leave urgent sorry bye
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kk
sorry sparks were coming from the socket..
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