you parents have $20,000 in the bank for your college education. in how many years can they have the amount of $60,000 to pay for college expends if the annual interest is 6% and it is compounded continuously? *formula: Q(t)= Q initial e^rt
Q(t)=60,000 Q= 20,000 r=0.06 Divide both sides by 20,000... Then you can ln both sides to get rid of the e.
can you show me how to do that please?
whats the eqation?
60,000 = 20,000e^(0.06t) 3=e^(0.06t) ln 3=lne^(0.06t)
\[60000 = 20000 e ^{0.06t}\] \[60000/20000 = 20000/20000 e ^{0.06t}\] \[3 = e ^{0.06t}\] \[ln(3) = 0.06t}\] \[ln(3)/0.06 = t}\]
so the final answer is ln(3)/0.06 = t}?
\[t = ln(3)/0.06\] yes
my calculator says 18.3
i have a TI-84 graphong calculator and my teacher didnt rlly teach me how to use it. so wheres the ln button?
never mind got it!
:)
I will need one of those graphing calculators for my next sem
what math are you taking atm?
advance calculus and differential equations, starting sept.
sounds scary... >.<
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