Question

On dividing Polynomials
2x^3-9x^2+15/2x-5

thanks in advance

Answer 1

2x^3-9x^2+15/2x-5
f(x)=2x^3-9x^2+15 by 2x-5
2x-5=0
x=5/2
f(x)=2(2.5)^3-9(2.5)^2+15
f(x)=-10

Answer 2

is ti right???

Answer 3

if it is then medal plz

Answer 4

x^2-2x-5-10/(5-2x)

Answer 5

anhhuyalex? what did you do?

Answer 6

x^2-2x-5-(10/(5-2x))?

Answer 7

akshay budhkar, yeah, your way is clearer

Answer 8

\[2x^3-9x^2+15\div2x-5\]

Answer 9

lol i just confirmed? coz i messed it up with the full as numerator and maybe the asker can do the same..

Answer 10

that's what i originally meant

Answer 11

anhhuyalex's answer is right i believe Oglon3r

Answer 12

x^2-2x+5-(10/2x-5)

Answer 13

thats what we r telling lol

Answer 14

yah thanks!

Answer 15

lol, you right

Answer 16

am i right or wrong

Answer 17

these godamn long divisions......

Answer 18

nick i am not getting what you did!

Answer 19

i did it in polynomial way
its in addmaths

Answer 20

by hoo song thong

Answer 21

nick got the residual of the division right now that I'm taking a closer look to it

Answer 22

WOW! what is that? i heard it for d first time

Answer 23

thanks everybody

Answer 24

\[\frac{2x^3-9x^2+15}{2x-5} = x^2 - 2x - 5 - \frac{10}{2x-5}\]

Everyone else's answers are wrong.

Answer 25

http://www.purplemath.com/modules/polys/divani04.gif

Answer 26

http://www.purplemath.com/modules/polys/div19.gif

Answer 27

Yes, actually. Akshay answered
\[x^2 - 2x - 5 - \frac{10}{5-2x}\]
which is most certainly not equal to
\[x^2 - 2x - 5 - \frac{10}{2x-5}\]
the latter of which is the correct polynomial that results from the division of the two polynomials that you cited in your question.

Answer 28

on the second gif in the final part they go something like this \[+ -10/2x-5\]

Answer 29

i answer that too
x^2-2x+5-(10/2x-5)
look carefully
if you want to out the minus you must do carefully
+ -10/2x-5
if being this - (10/-2x+5)
or - (10/5-2x)

Answer 30

thanks for clarifying it threw me off really bad for some reason haha its been a long night

Answer 31

no reason to threw you off oglon3r
i just explain to lollercakes
your explanation is right

Answer 32

Still wrong, dinainjune.

\[-\frac{10}{2x-5} \ne -\frac{10}{-2x+5}\] for all x, which is actually what you're implying.

Answer 33

lollercakes i like your confidence and the way you answer!
i will be your fan for that..
i am not verifying the answer now though as i am almost asleep but still nice way to answer

Answer 34

Thanks, Akshay.

Dinainjune, I assure you, my answer is correct.

Answer 35

it's really nice having different answer.
okay, if you sure of that lollercakes :)

Answer 36

http://www.wolframalpha.com/input/?i=%282x^3-9x^2%2B15%29%2F%282x-5%29 is the answer short cut lol

Answer 37

And here's the verification of my answer:

\[\frac{2x^3 - 9x^2 + 15}{2x - 5} = x^2 - 2x - 5 - \frac{10}{2x-5}\]
\[(x^2 - 2x - 5 - \frac{10}{2x - 5})(2x - 5) =\]
\[(x^2 + (-2x) + (-5) + (-\frac{10}{2x-5}))(2x - 5) = \]
\[x^2(2x - 5) + (-2x)(2x - 5) + (-5)(2x - 5) + (-\frac{10}{2x-5})(2x - 5) = \]
\[2x^3 - 5x^2 -4x^2 + 10x - 10x + 25 + (-1)\frac{10}{2x - 5}(2x - 5) = \]
\[2x^3 - 9x^2 + 25 + (-1)\frac{10(2x - 5)}{2x - 5} = \]
\[2x^3 - 9x^2 + 25 + (-1)*10 = \]
\[2x^3 - 9x^2 + 25 - 10 = \]
\[2x^3 - 9x^2 + 15\]

Answer 38

OMG!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 39

cool! Thank you for explaining

Answer 40

Hope it helps. (I'm not trying to be a jerk. I just want everyone to get why the answer is what it is.)

Answer 41

nope, if you don't do that.
i can't find my mistake and repair it
Thank you again!