Find two positive integers whose sum is 50 and the sum of their square is a minimum. I need solution please. :) Thanks!

Question

saifoo.khan · Answer

is a MINIMUM???

anonymous · Answer

Yes. I think that means that the answer should be the least of all sums of the square

anonymous · Answer

x+y= 50 and (x^2+y^2)= min.. 

thus differentiate x^2+ (50-x)^2 and equate that to zero.. and get x then get y!

anonymous · Answer

Our teacher said we should only use one variable. And that variable should be x. We cant use y.

anonymous · Answer

yea.. don't use y.. use x and 50-x as i mentioned!

myininaya · Answer

the reason he has x and y in the first two equations is because you can't write two positive integers whose sum is 50 and whose sum of their squares is a minimum without mentioning two variables
but you can always write our function min using one variable by solving the first equation

anonymous · Answer

is the answer 50?

anonymous · Answer

helloo. :)