how many ways are there to arrange the word ' success' such that all three 's' are separated?

Question

anonymous · Answer

do you have the answer

anonymous · Answer

is it 720?

akshay_budhkar · Answer

final answer is not important.. what is the method you used and?

anonymous · Answer

i wasn't sure about the answer so was just asking if the answer was known. i worked it out by multiplying 3!x5!

akshay_budhkar · Answer

why? 3!*5!?

anonymous · Answer

cause there are four other letters minus the 3 "s"

anonymous · Answer

i don't think I'm right though

anonymous · Answer

s-s-s--
s-s--s-
s-s---s
s--s-s-
s--s--s
s---s-s
-s-s-s-
-s-s--s
-s--s-s
--s-s-s

akshay_budhkar · Answer

whats this?

anonymous · Answer

ten possibilities to arrange the s's, the other letters don't  matter yet.

anonymous · Answer

so the answer is 10*4!

anonymous · Answer

4! for the other letters.

anonymous · Answer

hi sorry but i've no answer it's my test question today..

anonymous · Answer

my working's (4!x (4x3x2) )/3!x2!

zarkon · Answer

$${5\choose2}\cdot\frac{4!}{2!}$$

akshay_budhkar · Answer

Zarkon enters
Zarkon says answer is ...
Zarkon leaves
lol

zarkon · Answer

as shown above by Thomas9 there are 10 ways to arrange the blanks and s's which is
$${4+1\choose3}$$
the 4blanks and 3 s's

 the 4! is the arrangement of the 4 non s's. But we have 2 c's that can be arranged 2! ways. therefore we have
$$4!2!$$
ways to arrange the four non s's so the total number of ways to arrange is thus
$${4+1\choose3}⋅4!2!=10⋅4⋅3=120$$