Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

the Haulting question: say there was a computer program, decide whether the program finishes running or runs forever!?!?!

OpenStudy (dumbcow):

i dunno what program is it running? most programs would finish running but if it was stuck in a loop and had a infinite power source then who knows... :)

OpenStudy (anonymous):

dumb cow, if you dont mind me asking what are your credentials???

OpenStudy (dumbcow):

haha i have 1000 medals

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

The halting problem is about a program that has as input a different program and gives as output whether or not it stops. Apparently it doesn't exist.

OpenStudy (anonymous):

um... do you have a formal educational back groud, dumb cow?

OpenStudy (dumbcow):

are you really a student?

OpenStudy (anonymous):

thomas 9, that was an interesting responce

OpenStudy (anonymous):

but consider the sketch of proof

OpenStudy (owlfred):

1234 what type of credentials are you looking for?

OpenStudy (anonymous):

The proof was something with using the initial program as input, but I forgot most of it.

OpenStudy (anonymous):

My OS is supposed to run forever, doesn't though.

OpenStudy (anonymous):

lol

OpenStudy (zarkon):

I have a Ph.D. Galactic Domination(see profile). How's that?

OpenStudy (anonymous):

the proof shows there is no total computable function that decides whether an arbitrary program i halts on arbitrary input x: that is, the function h is not computable

OpenStudy (dumbcow):

galactic domination...!!?? interesting...

OpenStudy (anonymous):

thomas 9

OpenStudy (anonymous):

Not algorithmically decidable.

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

h(i,x)={1if program i halts on inputx, 0 otherwise

OpenStudy (anonymous):

Not recursive.

OpenStudy (zarkon):

yes...I looked at many universities, but Planet Doom University had the program that i really wanted. Great profeessors

OpenStudy (anonymous):

are you serious Zarkon?

OpenStudy (anonymous):

i have not heard from you thomas 9?

myininaya (myininaya):

galactic domination! i want that degree

myininaya (myininaya):

sounds hot and spicy

OpenStudy (anonymous):

Can I apply for Planet Doom University ?

OpenStudy (zarkon):

yes...the degree is in high demand

OpenStudy (anonymous):

estudier what do you think?

OpenStudy (zarkon):

you can...but the off planet tuition is a killer

OpenStudy (anonymous):

U have my opinion already.

myininaya (myininaya):

what kindof question is this, 1234?

OpenStudy (anonymous):

well what about my sketch of proof?

OpenStudy (anonymous):

Where is it?

OpenStudy (anonymous):

the proof he means not the university of doom.

OpenStudy (anonymous):

i am going to copy and repost my earlier responce

OpenStudy (anonymous):

the proof shows there is no total computable function that decides whether an arbitrary program i halts on arbitrary input x: that is, the function h is not computable

OpenStudy (anonymous):

The proof sketch, not PDUni.

OpenStudy (shadowfiend):

1234portion -- I didn't see a sketch of a proof. You stated the problem correctly, however.

OpenStudy (zarkon):

it is not the university of doom...that place it just a diploma mill. Planet Doom University is where I went

OpenStudy (shadowfiend):

The proof itself, at least in the original form presented by Alan Turing, involves defining what a computer is and describing how it runs a program (the then-named Turing machine is the machine that Turing posited for this). I believe you can also prove the same thing using the lambda calculus.

OpenStudy (owlfred):

1234 Portion, is this your first day on the site?

OpenStudy (anonymous):

h(i,x)={1if program i halts on inputx, 0 otherwise here program i refers to the i program in an enumeratio of all the programs of a fixed turing complete model of computation.

OpenStudy (anonymous):

that was for you e studier

OpenStudy (anonymous):

yes to your question owlfred

OpenStudy (owlfred):

okay cool, how did you find us?

OpenStudy (anonymous):

browsing... who are you exactly mr.owl?

OpenStudy (anonymous):

with the utmost respect of course

OpenStudy (anonymous):

...

OpenStudy (shadowfiend):

Heh. He's the OpenStudy mascot/moderator in chief.

OpenStudy (anonymous):

and who are you exactly??

OpenStudy (shadowfiend):

The Chief Software Engineer at OpenStudy.

OpenStudy (anonymous):

cool

OpenStudy (anonymous):

maby you can answer my question?

OpenStudy (anonymous):

Asked and answered.

OpenStudy (shadowfiend):

I'm not sure what exactly your question is :) Do you want a full proof for the undecidability of the halting problem?

OpenStudy (owlfred):

Haha, yeah sorry. I'm a moderator on OpenStudy.

OpenStudy (anonymous):

well thank you for your input e studier

myininaya (myininaya):

i say let the computer program run forever

myininaya (myininaya):

lol

OpenStudy (anonymous):

lol @ myin

myininaya (myininaya):

and let the machines take over

OpenStudy (zarkon):

10 print "hello" 20 goto 10 what about this

OpenStudy (anonymous):

Q "decide whether" A algorithmically undecidable.

OpenStudy (shadowfiend):

The question of the halting problem is for the general case. Given an arbitrary program, decide whether the program will end or not. It is impossible to write a program that will answer this question every time. It *is* possible to write a program that will answer this question sometimes.

OpenStudy (anonymous):

estudier you can try to single out possible values for a total computable function, if you have all the variables and an algorithm in place, cant you???

OpenStudy (anonymous):

shadow friend that is very intriguing, elaborate!

OpenStudy (shadowfiend):

Not sure what you're asking. Can you give an example?

OpenStudy (anonymous):

just explain more in detail about you response shadow friend, and like i said to estudieryou can try to single out possible values for a total computable function, if you have all the variables and an algorithm in place, cant you???

OpenStudy (anonymous):

A more interesting question is quantifying undecidability, or complexity in general.

OpenStudy (anonymous):

i am not sure my computer can even run as long as this thread

OpenStudy (anonymous):

e studier do you know of any powerful computer programs that postulate very complex and abstract mathematical information?

OpenStudy (anonymous):

and if you dont mind me asking what are your credentials ??? estudier?

OpenStudy (anonymous):

satelllite md phd psyd do dsw dch university of the galaxy (online)

OpenStudy (anonymous):

how many were bought online

OpenStudy (anonymous):

i got them for free well i did have to buy the candy bars

OpenStudy (anonymous):

what is up with you satellite73???

OpenStudy (zarkon):

lol

OpenStudy (anonymous):

i dont find this funny

OpenStudy (anonymous):

what ever happened to shadow friend?

OpenStudy (zarkon):

University of the Galaxy ...oooohhh...very prestigious!!

OpenStudy (anonymous):

yeah we used to kick your butts in lacrosse too !

OpenStudy (zarkon):

yeah...we suck. :(

OpenStudy (anonymous):

girls team did anyway

OpenStudy (shadowfiend):

All right, all right, stay on topic. If you want to talk about the University of the Galaxy, go do it in chat.

OpenStudy (anonymous):

was there a topic or just a credential check?

OpenStudy (shadowfiend):

Heh. Ignore the credential check ;) The topic at hand is the halting problem.

OpenStudy (shadowfiend):

As for my response, I'm just saying that the question of the halting problem is for the general case of any program. You can write a program that recognizes common patterns of programs that halt or don't. You can also decide the halting problem if you're not talking about a general purpose (or Turing-complete) programming language.

OpenStudy (anonymous):

i understand shadowfriend, however i like to know people educational back ground so i know how capable they are in math, but with that been said, why arent satellit73 talking about my problem, he or she i talking about some space university!

OpenStudy (anonymous):

it makes no sense !

OpenStudy (anonymous):

We judge here by deeds not words...

OpenStudy (anonymous):

come again e studier???

OpenStudy (anonymous):

where did that come from?

OpenStudy (anonymous):

That is my response to your persistent credential checks, has anyone asked for yours?

OpenStudy (anonymous):

we should not judge period, who are we to do so?

OpenStudy (anonymous):

you said we judge by deeds

OpenStudy (anonymous):

Correct, then the credential checks serve no useful purpose...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!